What do you get?

Someone solve my potential brain fart.

(yes that's an integral sign)

-------
Fook meplz.

---

1/100(x^2+5)^100

---

yeah, this must be a typo. thanks.

-------
Fook meplz.

---

Im pretty sure my teacher made a mistake cause ive done this problem over and over and i don't see the answer im getting as one of the options, and I'm pretty sure I'm doing it right.

What do you get?

Someone solve my potential brain fart.

(yes that's an integral sign)

---

Alright well, this is quite a simple question. We notice that if we differentiate x^2 + 5, then we will end up getting 2x + 0 or just 2x. We don't need to worry about the exponent just yet. So, we can substitute u = x^2+5, so du = 2xdx and we get:
Int[u^99 du
This is quite easy to solve and so we get:
[(u^100) / 100] + C, C = constant we don't know
Recall, u = x^2 + 5,
(x^2 + 5)^100 / 100 + C

We can check to ensure our answer is correct:
CHECK:
If we differentiate (x^2+5)^100 / 100, we should get 2x(x^2+5)^99. We quickly realize that we will need to know the Chain Rule and Power Rule. By the Power Rule, the exponent of 100 comes "down", cancelling out with 1/100, yielding (x^2+5)^99. To finish our differentiation, we must differentiate x^2+5, which is 2x. So, by the Chain Rule we will end up getting 2x(x^2+5)^99.

Therefore, our solution is correct.  

-------
Specialist in biology and minor in organic chemistry
Isn't science wonderful?

And oops forgot that +C on mine, my calculus teacher would be ashamed.

I was only struggling with it because my teacher made a typo and the correct answer isn't listed. I thought I may have been missing something, but I wasn't.

Thanks both.

-------
Fook meplz.