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If you can solve this, I'd be so grateful.
Replies: 15Last Post Nov. 20, 2008 11:41am by Krebons
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( Anonymous )

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Brutus, a champion weightlifter, raises 221 kg of weights a distance of 2.45 m.

How much work is done by Brutus lifting the weights?

I can't figure it out, because I thought Work= Force x Distance.

But the force isn't given here. But doesn't F= mass x acceleration? but there's no acceleration here?

And I know the answer isn't 0.

*confused*


3:26 am on Nov. 20, 2008
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Rollo Tomasi


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acceleration is 9.8 m/s^-2

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3:27 am on Nov. 20, 2008 | Joined: Oct. 2006 | Days Active: 423
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Rollo Tomasi


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you know...gravity?

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3:28 am on Nov. 20, 2008 | Joined: Oct. 2006 | Days Active: 423
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( Anonymous )

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Quote: from Rollo Tomasi at 3:27 am on Nov. 20, 2008

acceleration is 9.8 m/s^-2

Are you saying the acceleration is negative?

I see a -2 there.


3:28 am on Nov. 20, 2008
Rollo Tomasi


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...god damn son, you need a lot more help than i can give you

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3:29 am on Nov. 20, 2008 | Joined: Oct. 2006 | Days Active: 423
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JohnTheNormalOne


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the answer is 42

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3:29 am on Nov. 20, 2008 | Joined: Mar. 2007 | Days Active: 379
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( Anonymous )

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Quote: from Rollo Tomasi at 3:29 am on Nov. 20, 2008

...god damn son, you need a lot more help than i can give you

Leave.


3:29 am on Nov. 20, 2008
Rollo Tomasi


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i will, but i take comfort knowing that only one of us here is stupid.

and because i know you won't be able to figure out which one of us it is, i am also here to tell you that it is you who is stupid.

hth.

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3:31 am on Nov. 20, 2008 | Joined: Oct. 2006 | Days Active: 423
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Killtyronedead


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Quote: from Anonymous at 6:28 am on Nov. 20, 2008

Quote: from Rollo Tomasi at 3:27 am on Nov. 20, 2008

acceleration is 9.8 m/s^-2

Are you saying the acceleration is negative?

I see a -2 there.



Wow.  You're not very bright.

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3:36 am on Nov. 20, 2008 | Joined: Feb. 2007 | Days Active: 685
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FurryPanther

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Gravity is acceleration in the direction opposite the one of motion, namely down when the weight is moving up.

W = F x d
F = m x a

Therefore:

W = m x a x d

W = 221kg x 9.8m/s^2 x 2.45m

Also, Rollo Tomasi's notation is correct.

W = 221kg x 9.8ms^-2 x 2.45m

This results in:

W = 5306.21 J
W = 5.3 kJ

There you go. That was immensely simple. I think you need a tutor. Badly.

FP

Post edited at 3:46 am on Nov. 20, 2008 by FurryPanther

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roflfuckyou



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i get 5306.21J as the work

don't know if it's right though.


3:45 am on Nov. 20, 2008 | Joined: June 2008 | Days Active: 445
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FurryPanther

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Quote: from roflfuckyou at 4:45 am on Nov. 20, 2008

i get 5306.21J as the work

don't know if it's right though.


That's right. 5.3kJ with significant figures.

FP

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3:46 am on Nov. 20, 2008 | Joined: June 2006 | Days Active: 645
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roflfuckyou



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yeah i just did
sum of the forces = m x a
a = gravity
m = 221kg

then i did w = f x d
f = 2165.8
d = 2.45

so work = 5306.21j


3:47 am on Nov. 20, 2008 | Joined: June 2008 | Days Active: 445
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Fishboner

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The OP fails at math.

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S = k Log W | Trial and Terror.
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roflfuckyou



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Quote: from FurryPanther at 10:46 pm on Nov. 20, 2008

Quote: from roflfuckyou at 4:45 am on Nov. 20, 2008

i get 5306.21J as the work  

 don't know if it's right though.


That's right. 5.3kJ with significant figures.

FP



yay i retained something from a years work of physics (:

3:59 am on Nov. 20, 2008 | Joined: June 2008 | Days Active: 445
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