10:41 pm on Dec. 8, 2008 | Joined: Jan. 2006 | Days Active: 539 Join to learn more about One Two StepSpain | Female | Posts: 11,276 | Points: 17,618
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SparklingFlower
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I used to know how to do this. I'm majoring in accounting. and now I'm depressed.
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AcidSilence
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well, subsitute. f(x)=3x+5 and g(x)=x squared.
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hi sarah
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(f+g)(x) = x(x^2 + 3x + 5) = x^3 + 3x^2 + 5x
(f over g)(x) = (3x + 5/x^2)x = uhh 3x + 5/x?
not sure on the last one
Post edited at 10:44 pm on Dec. 8, 2008 by hi sarah
10:44 pm on Dec. 8, 2008 | Joined: June 2008 | Days Active: 469 Join to learn more about hi sarahSenegal | Label Free | Posts: 17,722 | Points: 40,276
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Quote: from AcidSilence at 10:42 pm on Dec. 8, 2008
well, subsitute. f(x)=3x+5 and g(x)=x squared.
How can I substitute for only f and g when they give the function of f and g..
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Desertfoxel
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my brain hurts just by reading the equations
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Just Waiting Here
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You just plug them in...
f(x) - 3x + 5 g(x) = x^2.
The first one says (f+g)(x) That just means you add the functions together...
(f+g)(x) = f(x) + g(x)
For the second one... it's...
f(x)/g(x). Just plug in the values, and those are your answers.
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well, subsitute. 
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