What is the max height it will reach?

Can someone help me out?

I'm sorry I haven't taken a physics class in two years.

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LW's resident eccentric radical.

You gotta find the y component of the velocity, so you would do sin(57) x 46 m/s.  Then you get the y component speed.  Then you need to find the total kinetic energy the object has, using the equation 1/2(mass)(velocity)^2.  You don't have mass, but it will cancel out later anyway, so its ok.

So then you have the kinetic energy which is   "blahblahblah(mass)"  and you set that equal to (mass)(accel due to gravity)(height).  The kinetic energy must equal the potential energy at the highest point.

So the masses from each side of the equation cancel out.

Then you get some number = (accel due to gravity)(height).

So then you divide the left by the accel due to gravity, and you get the height

sorry i don't have a calculator so i can't do the sin 57 part.

sin(57) = y/46
y=46*sin(57)
y=38.58ms^-1

You know the velocity at the top is going to be 0ms^-1 and acceleration is -9.8ms^-2
So
v^2=u^2+2ax
0=148.83-19.6x
x=148.83/19.6
x=75.94m

So the object goes up 75.94 metres.

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"We were starting to establish some trust.  Except for all the lies."

Now, you go back to your standard kinematic equations...

The maximum height will be reached at the exact point the object is no longer traveling upwards, so using the equation V=Vo + AT, you can solve for T (time)

0=38.6 + -9.8T

9.8T = 38.6

9.8T/9.8 = 38.6/9.8

T = 3.94 seconds

Now, go back to the equations...

S = So + VoT + 1/2AT^2

S = 0 + 38.6x3.94 + .5x-9.8x3.94^2

S = 152.8 + -4.9x15.52

S = 152.8 - 76.05

S = 76.75 meters in the air.

If you need more clarification, message me.

solve, dont have a calculator on hand