Pretty straight forward. I would start by drawing the sulfur... it will have six electrons on the outside. Two groups of two and two groups of one. Now, you have CH3, and since they grouped it together like this, it suggests it's as a methyl group. So you'll have two CH3 groups... so that will leave just one more electron on each methyl to bond with the sulfur. If you draw one methyl group on either side of the sulfur, then you will notice that you can draw bonds between the single electron left on C to the S... You'll have something that looks like this.
H3C -- S -- CH3
Now... from before, you had two pairs of electrons on the sulfur, and those have stayed there. There are non on Carbon or hydrogen.
So you would have two non-bonding electron pairs in your dimethyl sulfide.
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