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  LiveWire / Teen Forums / School & Homework Connection / Viewing Topic

Calling math geeks, points awarded.
Replies: 19Last Post Nov. 8 4:05am by Manipulative Acid
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( Manipulative Acid )


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Okay, so you know the equation (x-x1)+(y-y1)=r2(radius squared) to get the centre of a circumference right?

You're given two points defined by (2,3) and (4,5) or something in the circumference.
So do you first get the radius by the equation: squared root of (x2-x1)+(y2-y1) ?

Then you use that as the radius, but then what do you do with the first equation?

Loads of points offered if you can properly explain.

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12:31 pm on Nov. 5, 2009 | Joined: Dec. 2007 | Days Active: 326
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math.com

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12:33 pm on Nov. 5, 2009 | Joined: Sep. 2008 | Days Active: 315
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Spuddlesworth


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There are many circles you could draw which pass through those two points.

Is there any more information in the question?  Is the centre of the circle specificed, or maybe it says that those two points are diametrically opposite (i.e. the distance between them is the diameter of the circle)?

Happy to help if you let me know :)


12:34 pm on Nov. 5, 2009 | Joined: July 2005 | Days Active: 553
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basically your your coordinates are X1, X2 ect.

2 = X
4 = X1
3 = Y
5= Y1

your just imputting these numbers into the first equation to get the radius. so
(2-4)+ (3-5) = r2.
sqaure route the answer and thats the radius.


12:34 pm on Nov. 5, 2009 | Joined: Nov. 2009 | Days Active: 3
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Spuddlesworth


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Quote: from SanityAsylum at 8:34 pm on Nov. 5, 2009

basically your your coordinates are X1, X2 ect.  

2 = X
4 = X1
3 = Y  
5= Y1  

your just imputting these numbers into the first equation to get the radius. so  
(2-4)+ (3-5) = r2.  
sqaure route the answer and thats the radius.


Wrong.

This is only true if the centre of the circle is (4,5).

Unless the question specified this to be the case.


12:37 pm on Nov. 5, 2009 | Joined: July 2005 | Days Active: 553
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SanityAsylum


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Quote: from Spuddlesworth at 12:37 pm on Nov. 5, 2009

Quote: from SanityAsylum at 8:34 pm on Nov. 5, 2009

basically your your coordinates are X1, X2 ect.

 2 = X  
 4 = X1  
 3 = Y
 5= Y1

 your just imputting these numbers into the first equation to get the radius. so
 (2-4)+ (3-5) = r2.
 sqaure route the answer and thats the radius.


Wrong.

This is only true if the centre of the circle is (4,5).

Unless the question specified this to be the case.


Touché (: i was just going with the little info given and what little knowledge of maths i have.
didn't expect to be right... call it wishful thinking.


12:41 pm on Nov. 5, 2009 | Joined: Nov. 2009 | Days Active: 3
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( Manipulative Acid )


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Quote: from Spuddlesworth at 8:34 pm on Nov. 5, 2009

There are many circles you could draw which pass through those two points.

Is there any more information in the question? Is the centre of the circle specificed, or maybe it says that those two points are diametrically opposite (i.e. the distance between them is the diameter of the circle)?

Happy to help if you let me know :)


Um... I kind of suck at translating all of this into English from Portuguese, but it's something like this:

All you get is four points, and this is the actual question:
A(2,3), B(4,6), C(5,2) and D(2,6)

I think C is the centre of the circumference.
First question is to determine the distance between A and B. I did it and the answer was square root of 13.

So I've got (x-x1)+(y-y1)=r2(radius squared), and then I can substitute the r2 by square root of 13, but what do I substitute the x1 and y1 for?
Is it C?


Sorry if it made no sense, it's hard to explain.

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12:43 pm on Nov. 5, 2009 | Joined: Dec. 2007 | Days Active: 326
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Spuddlesworth


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Quote: from MANIpulative ACID at 8:43 pm on Nov. 5, 2009

Quote: from Spuddlesworth at 8:34 pm on Nov. 5, 2009

There are many circles you could draw which pass through those two points.  

 Is there any more information in the question?  Is the centre of the circle specificed, or maybe it says that those two points are diametrically opposite (i.e. the distance between them is the diameter of the circle)?  

 Happy to help if you let me know :)


Um... I kind of suck at translating all of this into English from Portuguese, but it's something like this:

All you get is four points, and this is the actual question:
A(2,3), B(4,6), C(5,2) and D(2,6)

I think C is the centre of the circumference.
First question is to determine the distance between A and B. I did it and the answer was square root of 13.

So I've got (x-x1)+(y-y1)=r2(radius squared), and then I can substitute the r2 by square root of 13, but what do I substitute the x1 and y1 for?
Is it C?

 
Sorry if it made no sense, it's hard to explain.


Do you mean, B is (4,5)?


12:47 pm on Nov. 5, 2009 | Joined: July 2005 | Days Active: 553
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( Manipulative Acid )


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Nope, sorry, I did it wrong in the first place.

B is (4,6)

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12:51 pm on Nov. 5, 2009 | Joined: Dec. 2007 | Days Active: 326
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Quote: from maNIPULative acid at 8:51 pm on Nov. 5, 2009

Nope, sorry, I did it wrong in the first place.

B is (4,6)


:) okay, are the other points you said correct?


12:53 pm on Nov. 5, 2009 | Joined: July 2005 | Days Active: 553
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( Manipulative Acid )


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Quote: from Spuddlesworth at 8:53 pm on Nov. 5, 2009

Quote: from maNIPULative acid at 8:51 pm on Nov. 5, 2009

Nope, sorry, I did it wrong in the first place.  

 B is (4,6)


:) okay, are the other points you said correct?


Yes everything else is correct.

And the my answer for the distance between A and B was square root of 13...

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12:54 pm on Nov. 5, 2009 | Joined: Dec. 2007 | Days Active: 326
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Spuddlesworth


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You're correct that the distance between A and B is √13, but I'm not sure what you're meant to do then.

I don't think any of the points are meant to be centres of circles; none of the other points line up on them.

If you make the centre of the circle between A and B, the circle will go through D but not C (with a radius of (√13)/2).

I wish I could help more but I'm not sure what the question's asking!


1:00 pm on Nov. 5, 2009 | Joined: July 2005 | Days Active: 553
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Quote: from Spuddlesworth at 9:00 pm on Nov. 5, 2009

You're correct that the distance between A and B is √13, but I'm not sure what you're meant to do then.

I don't think any of the points are meant to be centres of circles; none of the other points line up on
them.

If you make the centre of the circle between A and B, the circle will go through D but not C (with a radius of (√13)/2).

I wish I could help more but I'm not sure what the question's asking!


Hmm I know it doesn't say much and a bunch of equations are thrown at me.

I think C is the centre, and the rest I am pretty sure are points in the circumference.

Would it make sense like this?

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1:02 pm on Nov. 5, 2009 | Joined: Dec. 2007 | Days Active: 326
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Spuddlesworth


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Quote: from maNIPULative acid at 9:02 pm on Nov. 5, 2009

Quote: from Spuddlesworth at 9:00 pm on Nov. 5, 2009

You're correct that the distance between A and B is √13, but I'm not sure what you're meant to do then.  

 I don't think any of the points are meant to be centres of circles; none of the other points line up on  
them.  

 If you make the centre of the circle between A and B, the circle will go through D but not C (with a radius of (√13)/2).  

 I wish I could help more but I'm not sure what the question's asking!


Hmm I know it doesn't say much and a bunch of equations are thrown at me.

I think C is the centre, and the rest I am pretty sure are points in the circumference.

Would it make sense like this?


All the points are different distances from each other, if they all lay on the same circle with one of the points as the centre then they'd all be equidistant from one point  

C can't be the centre, A is 3 units away from it, B is √17 units away from it and D is five units away from it.

Sob

I fail  


1:15 pm on Nov. 5, 2009 | Joined: July 2005 | Days Active: 553
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