This is a physics problem...and of course I have no reason why its a body or whatever.

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The less time we have, the more we accomplish, the more we end up doing.
Love is the same

d = st
  = 29.43 * 3
  = 88.29 m

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Penultimate just means second to last you pretentious f*ck.

That's not a riot it's a feast, let's eat!

d = d0 + v0t + (1/2)at^2

d0 is the initial displacement, v0 is the intial speed, a is your acceleration.

In your problem...

d0 = 0, v0=0, and a is gravity, which is a= -9.8 m/s^2

Plug in what you have, and you will find your displacement.

Post edited at 2:12 pm on Nov. 9, 2009 by Just Waiting Here

s = 0 + 1/2(9.81)(3ē)

= 44.145 m = 44.1 m (3.s.f.)

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The body will fall at the rate of gravity, so 9.81 * 3 = 29.43ms^-1

d = st
  = 29.43 * 3
  = 88.29 m

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I get precisely half this.

Btw, the object starts at rest.  It's not falling at 3g constantly, which you appear to be suggesting.

In this problem it never falls at constant speed, we just assume it keeps accelerating at 9.81m/sē

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Quote: from Frubeling at 10:05 pm on Nov. 9, 2009

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The body will fall at the rate of gravity, so 9.81 * 3 = 29.43ms^-1  

 d = st  
   = 29.43 * 3  
   = 88.29 m

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I get precisely half this.

Btw, the object starts at rest. It's not falling at 3g constantly, which you appear to be suggesting.

In this problem it never falls at constant speed, we just assume it keeps accelerating at 9.81m/sē

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