26.20 ml of 0.102 M NaOH is needed to neutralize 25/00 ml of an unknown acid HA. The pH at the equivalence point was measured to be 8.77. what is the Ka of this acid?
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switchfoot52
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just drop out. that stuff makes my head hurt
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agrayson22
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26.20 ml x 0.102 M NaOH -25/00 ml 8.77.?
its an alcilie
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