Thats a balanced equation above. Every number that isnt bold should be a little one, i.e H2O is waster and 2H2O is 2 molecules of water.

I'm having trouble. Can someone help me figure out which is the limiting reactant? I cant do it, I dont even know where to start.

Post edited at 5:09 am on Oct. 11, 2008 by ElephantStone

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Though from what I can see you need to have some given quantities, ie, masses, of the substances in order to determine the limiting factor. Unless that's given I don't really see how you can determine the limiting factor.

In all cases you need to work out how many moles of each substance you have in your example (and not just in the equation). As moles = mass / RFM, you need to know the mass of the first two reagents. Do you not know them?

You can't just use '1' for each, because the equation is balanced and in that case neither are limiting factors because it is perfectly balanced.

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Intelligence is the ability to avoid doing work, yet getting the work done.

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H2(C4H2O6) + NaH(CO3) --> Na2(C4H2O6) + 2H2O + 2CO2

Thats a balanced equation above. Every number that isnt bold should be a little one, i.e H2O is waster and 2H2O is 2 molecules of water.

I'm having trouble. Can someone help me figure out which is the limiting reactant? I cant do it, I dont even know where to start.

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You fk'in balanced it wrong - that is not a balanced equation.

Answer: H2(C4H206) + 2(NaH(CO3)) => Na2(C4H206) + H20 + 2C02

I'm not going to answer what is the limiting reactant.

Damn, I haven't done chemistry in what like 3-4 years.

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So the limiting reagent can be defined as "The chemical of which there are fewer moles than the proportion requires is the limiting reagent."

Though from what I can see you need to have some given quantities, ie, masses, of the substances in order to determine the limiting factor. Unless that's given I don't really see how you can determine the limiting factor.

In all cases you need to work out how many moles of each substance you have in your example (and not just in the equation). As moles = mass / RFM, you need to know the mass of the first two reagents. Do you not know them?

You can't just use '1' for each, because the equation is balanced and in that case neither are limiting factors because it is perfectly balanced.

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ok if you need to see it the origional equation was

H2(C4H2O6) + NaH(CO3)  Na2(C4H2O6) + H2O + CO2

before I balanced it. it says theres 50g of each reagent, so I woeked that out as 0.338 moles for the first one and 0.595 moles for the second one.

Any idea now?

Im still lost.

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Future. Sex. Love. Sound.
Just tell me which way you like it.

but fuck it, how many moles of CO2 are produced?

I really, really fucking hate chemistry

Post edited at 5:25 am on Oct. 11, 2008 by ElephantStone

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Future. Sex. Love. Sound.
Just tell me which way you like it.