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Siress
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Posted at 9:39 pm on Sep. 23, 2008 |
No, Carmen. No. (a+b)(a-b)!=a+b(a-b)!=a^2-b^2 != means not equal. Permious has been correct on everything I've read. |
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carmen2487
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Posted at 7:48 pm on Sep. 23, 2008 |
a^2-b^2=a+b(a-b) =] |
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2kewl4u2know
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Posted at 7:42 pm on Sep. 23, 2008 |
Quote: from Permious at 9:39 pm on Sep. 23, 2008
the rule is x^3 - y^3 = (x - y)(x^2 + xy + y^2) so w^3 - 125 = w^3 - 5^3 = (w - 5)(w^2 + 5w + 25) which can't be factorised any further 
Yeah..I see that now...tonight is just a horrible night for math for me |
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Permious
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Posted at 7:39 pm on Sep. 23, 2008 |
| the rule is x^3 - y^3 = (x - y)(x^2 + xy + y^2) so w^3 - 125 = w^3 - 5^3 = (w - 5)(w^2 + 5w + 25) which can't be factorised any further |
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classicalandrew
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Posted at 7:36 pm on Sep. 23, 2008 |
| i agree with permious...lol |
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2kewl4u2know
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Posted at 7:36 pm on Sep. 23, 2008 |
Quote: from Permious at 9:34 pm on Sep. 23, 2008
(s - 1 - 8f)(s - 1 + 8f) = s(s - 1 + 8f) - 1(s - 1 + 8f) - 8f(s - 1 + 8f) = s^2 - s + 8fs - s + 1 - 8f - 8fs - 8f - 64f^2 = s^2 - 2s + 1 - 64f^2 yep i was totally right 
Hold on...I think my boyfriend is just typing it all in wrong...starting to piss me off. Another problem asked for w^3 - 125 factored, and I gave him (w-5)^2(w+5) and it said it was wrong...because it didn't want that simplified of an answer. FUCKING starting to piss me off. |
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Permious
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Posted at 7:34 pm on Sep. 23, 2008 |
| (s - 1 - 8f)(s - 1 + 8f) = s(s - 1 + 8f) - 1(s - 1 + 8f) - 8f(s - 1 + 8f) = s^2 - s + 8fs - s + 1 - 8f - 8fs - 8f - 64f^2 = s^2 - 2s + 1 - 64f^2 yep i was totally right |
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2kewl4u2know
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Posted at 7:32 pm on Sep. 23, 2008 |
Quote: from Permious at 9:31 pm on Sep. 23, 2008
Quote: from 2kewl4u2know at 7:30 pm on Sep. 23, 2008
Quote: from Permious at 9:27 pm on Sep. 23, 2008
Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008
Math=heartache. 
math is fucking awesome 
Looks like we were all wrong...the answer was: (s-1+8f)^2 (s-1-8f)^2 
wtf that answer is fucking wrong it should be (s - 1 + 8f)(s - 1 - 8f) fucking trust me 
The math program my boyfriend (who I'm helping with these) is using fucking sucks... |
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Permious
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Posted at 7:31 pm on Sep. 23, 2008 |
if you multiply out what i just wrote you WILL get s^2 - 2s + 1 - 64f^2 |
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Permious
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Posted at 7:31 pm on Sep. 23, 2008 |
Quote: from 2kewl4u2know at 7:30 pm on Sep. 23, 2008
Quote: from Permious at 9:27 pm on Sep. 23, 2008
Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008
Math=heartache. 
math is fucking awesome 
Looks like we were all wrong...the answer was: (s-1+8f)^2 (s-1-8f)^2 
wtf that answer is fucking wrong it should be (s - 1 + 8f)(s - 1 - 8f) fucking trust me |
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2kewl4u2know
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Posted at 7:30 pm on Sep. 23, 2008 |
Quote: from Permious at 9:27 pm on Sep. 23, 2008
Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008
Math=heartache. 
math is fucking awesome 
Looks like we were all wrong...the answer was: (s-1+8f)^2 (s-1-8f)^2 |
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HuffleHaire
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Posted at 7:29 pm on Sep. 23, 2008 |
Quote: from peace love sunshine at 9:21 pm on Sep. 23, 2008
it looks simplified to me.
No. |
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Permious
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Posted at 7:27 pm on Sep. 23, 2008 |
Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008
Math=heartache. 
math is fucking awesome |
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MixedDelight
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Posted at 7:27 pm on Sep. 23, 2008 |
| Math=heartache. |
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2kewl4u2know
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Posted at 7:25 pm on Sep. 23, 2008 |
Quote: from Permious at 9:23 pm on Sep. 23, 2008
Quote: from 2kewl4u2know at 7:22 pm on Sep. 23, 2008
Quote: from Permious at 9:20 pm on Sep. 23, 2008
s^2 - 2s + 1 = (s - 1)^2 it's the diff of two squares a^2 - b^2 = (a - b)(a + b) 
You neglected the -64f^2...and it's not set equal to 0...so I don't think you can do that... 
wtf i didnt neglect it at all i'm just informing you that s^2 - 2s + 1 = (s - 1)^2 and that you then have a difference of two squares and of course you can do it a^2 - b^2 is always equal to (a - b)(a + b) 
Sorry...I was forgetting that you can do that...the lack of parentheses threw me off...I feel like a goof |
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