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  LiveWire / College Forums / Classes & Exams / Adding Reply

Adding Reply
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Topic gosh...any ideas about how to go about doing this problem???
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Original Post
2kewl4u2know Posted at 7:19 pm on Sep. 23, 2008
Usually I'm good with this stuff but...

s^2 - 2s + 1 - 64f^2

Any idea how to factor this?

Replies
Siress Posted at 9:39 pm on Sep. 23, 2008
No, Carmen. No. (a+b)(a-b)!=a+b(a-b)!=a^2-b^2
!= means not equal.

Permious has been correct on everything I've read.

carmen2487 Posted at 7:48 pm on Sep. 23, 2008
a^2-b^2=a+b(a-b)
=]
2kewl4u2know Posted at 7:42 pm on Sep. 23, 2008
Quote: from Permious at 9:39 pm on Sep. 23, 2008

the rule is x^3 - y^3 = (x - y)(x^2 + xy + y^2)

so w^3 - 125 = w^3 - 5^3 = (w - 5)(w^2 + 5w + 25) which can't be factorised any further


Yeah..I see that now...tonight is just a horrible night for math for me    

Permious Posted at 7:39 pm on Sep. 23, 2008
the rule is x^3 - y^3 = (x - y)(x^2 + xy + y^2)

so w^3 - 125 = w^3 - 5^3 = (w - 5)(w^2 + 5w + 25) which can't be factorised any further

classicalandrew Posted at 7:36 pm on Sep. 23, 2008
i agree with permious...lol
2kewl4u2know Posted at 7:36 pm on Sep. 23, 2008
Quote: from Permious at 9:34 pm on Sep. 23, 2008

(s - 1 - 8f)(s - 1 + 8f)

= s(s - 1 + 8f) - 1(s - 1 + 8f) - 8f(s - 1 + 8f)

= s^2 - s + 8fs - s + 1 - 8f - 8fs - 8f - 64f^2

= s^2 - 2s + 1 - 64f^2

yep i was totally right


Hold on...I think my boyfriend is just typing it all in wrong...starting to piss me off.  Another problem asked for w^3 - 125 factored, and I gave him (w-5)^2(w+5) and it said it was wrong...because it didn't want that simplified of an answer.

FUCKING starting to piss me off.

Permious Posted at 7:34 pm on Sep. 23, 2008
(s - 1 - 8f)(s - 1 + 8f)

= s(s - 1 + 8f) - 1(s - 1 + 8f) - 8f(s - 1 + 8f)

= s^2 - s + 8fs - s + 1 - 8f - 8fs - 8f - 64f^2

= s^2 - 2s + 1 - 64f^2

yep i was totally right

2kewl4u2know Posted at 7:32 pm on Sep. 23, 2008
Quote: from Permious at 9:31 pm on Sep. 23, 2008

Quote: from 2kewl4u2know at 7:30 pm on Sep. 23, 2008

Quote: from Permious at 9:27 pm on Sep. 23, 2008

Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008

Math=heartache.
   

   
math is fucking awesome


Looks like we were all wrong...the answer was:

(s-1+8f)^2 (s-1-8f)^2


 

wtf  

that answer is fucking wrong  

it should be  

(s - 1 + 8f)(s - 1 - 8f)  

fucking trust me


The math program my boyfriend (who I'm helping with these) is using fucking sucks...

Permious Posted at 7:31 pm on Sep. 23, 2008
if you multiply out what i just wrote you WILL get s^2 - 2s + 1 - 64f^2
Permious Posted at 7:31 pm on Sep. 23, 2008
Quote: from 2kewl4u2know at 7:30 pm on Sep. 23, 2008

Quote: from Permious at 9:27 pm on Sep. 23, 2008

Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008

Math=heartache.
 

 
 math is fucking awesome


Looks like we were all wrong...the answer was:

(s-1+8f)^2 (s-1-8f)^2


wtf

that answer is fucking wrong

it should be

(s - 1 + 8f)(s - 1 - 8f)

fucking trust me

2kewl4u2know Posted at 7:30 pm on Sep. 23, 2008
Quote: from Permious at 9:27 pm on Sep. 23, 2008

Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008

Math=heartache.

 
math is fucking awesome


Looks like we were all wrong...the answer was:

(s-1+8f)^2 (s-1-8f)^2

HuffleHaire Posted at 7:29 pm on Sep. 23, 2008
Quote: from peace love sunshine at 9:21 pm on Sep. 23, 2008

it looks simplified to me.

No.

Permious Posted at 7:27 pm on Sep. 23, 2008
Quote: from MixedDelight at 7:27 pm on Sep. 23, 2008

Math=heartache.


math is fucking awesome

MixedDelight Posted at 7:27 pm on Sep. 23, 2008
Math=heartache.
2kewl4u2know Posted at 7:25 pm on Sep. 23, 2008
Quote: from Permious at 9:23 pm on Sep. 23, 2008

Quote: from 2kewl4u2know at 7:22 pm on Sep. 23, 2008

Quote: from Permious at 9:20 pm on Sep. 23, 2008

s^2 - 2s + 1 = (s - 1)^2

  it's the diff of two squares

  a^2 - b^2 = (a - b)(a + b)


 

 You neglected the -64f^2...and it's not set equal to 0...so I don't think you can do that...


wtf

i didnt neglect it at all

i'm just informing you that s^2 - 2s + 1 = (s - 1)^2 and that you then have a difference of two squares

and of course you can do it

a^2 - b^2 is always equal to (a - b)(a + b)


Sorry...I was forgetting that you can do that...the lack of parentheses threw me off...I feel like a goof    

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