Adding Reply Archived Topic: It will not be bumped to the top of the forum. Topic i need help w/chem hw. Membername   Not a member? Sign Up Free (takes 20 seconds) Password   Forgotten your password? Post Font: Verdana Arial Black Georgia Comic Sans Impact   Size: Tiny Normal Big Huge   Color: Default Dark Red Red Orange Brown Green Olive Cyan Blue Dark Blue Indigo Black [ Check Spelling ] [ Post Preview ] [ LiveTags ] FAQ Keyword Search: Post Options Favorites Manager Notify me of new replies to this topic by email Notify me of new replies to this topic by private message Original Post a7m3l5a Posted at 4:32 pm on Oct. 6, 2008 can someone plz explain how to do this problem. 26.20 ml of 0.102 M NaOH is needed to neutralize 25/00 ml of an unknown acid HA. The pH at the equivalence point was measured to be 8.77. what is the Ka of this acid?

Replies agrayson22 Posted at 4:34 pm on Oct. 6, 2008 26.20 ml x 0.102 M NaOH -25/00 ml 8.77.? its an alcilie switchfoot52 Posted at 4:33 pm on Oct. 6, 2008 just drop out. that stuff makes my head hurt All 2 previous replies displayed.