Do you have the answers? cos(arccos 8) = 8
You wrote arccot... was that a typo, or is that actually what you need to solve? I solved for arc cos.
sin[arcsin 2/3] = 1/3
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2
Do you know what the relationship between sin and arc sin is... or the relationship between cos and arc cos?
Basically... they are inverse's of one another. So... if...
cos x = y then...
arccos y = x
This being said, when you take the cos or arccos, it's just the number that you have there. Let's take the general case.
Let...
cos y = x... then, by definition
arccos x = y
so... what is cos(arccos x)?
Well... arccos x = y. So we plug that in, and we get...
cos(arccos x) = cos (y). From above, we stated that cos y = x.
Therefore... cos y = x.
Using that in your first problem... the answer would just be 8 (if it was arc cos)
Similar steps are taken for the second problem. So it would just be (2/3)/2