-- Posted by a7m3l5a at 4:32 pm on Oct. 6, 2008 can someone plz explain how to do this problem. 26.20 ml of 0.102 M NaOH is needed to neutralize 25/00 ml of an unknown acid HA. The pH at the equivalence point was measured to be 8.77. what is the Ka of this acid? -- Posted by switchfoot52 at 4:33 pm on Oct. 6, 2008 just drop out. that stuff makes my head hurt -- Posted by agrayson22 at 4:34 pm on Oct. 6, 2008 26.20 ml x 0.102 M NaOH -25/00 ml 8.77.? its an alcilie