LiveWire Peer Support Network

Printable Version of Topic "factor this fully"

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-- Posted by youngage at 5:11 pm on July 6, 2009

a) 8x^3 - 1

b) x^3 + 64

c) 8/125x^3 - 64y^6

thanks again


-- Posted by Descartes at 5:15 pm on July 6, 2009

2x+1 2x+1 2x-1
x+4 x+4 x+4
I dont want to do the last one
THe first two may be wrong.


-- Posted by BleedingSteelWings at 5:15 pm on July 6, 2009

b)(x^2+16)(x+4)
c) (4/25x^2 - 16y^4)(2/5x - 4y^2)
I think.


-- Posted by youngage at 5:27 pm on July 6, 2009

how do you get it?

bleeding steel wings.


-- Posted by LiveForeverDieTonite at 5:33 pm on July 6, 2009

a) (x+4)(x^2-4x+16)
b) (2x-1)(2x^2-2x+1)


-- Posted by BleedingSteelWings at 5:38 pm on July 6, 2009

Quote: from youngage at 9:57 pm on July 6, 2009


how do you get it?

bleeding steel wings.



what do you mean how do you get it?
you just take one of the factors out of it. thats how you do the cubed ones.


-- Posted by blitzerdog at 8:41 pm on July 6, 2009

No the second and third ones are formulas.

(a+b)(a^2-ab+b^2)
(a-b)(a^2+ab+b^2)

b)(x+4)(x^2-4x+16)
c) (2/5x-4y^2)(4/25x^2+8/5xy+16y^4)


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